Jaylen Warren wins first AFC offensive player of the week award
NBC Sports • • sports
Key Points:
- Jaylen Warren led the Pittsburgh Steelers to a significant victory over the Indianapolis Colts, earning him the AFC Offensive Player of the Week award.
- Warren set a career-high with 188 yards from scrimmage, including 101 rushing yards, 87 receiving yards, and two touchdowns—one rushing and one receiving.
- He became the sixth player in NFL history, and the first in 40 seasons, to record a receiving touchdown of at least 80 yards and a rushing touchdown of at least 50 yards in the same game.
- This marks Warren's first Offensive Player of the Week award and the first for a Steelers player since Ben Roethlisberger in 2020.
- The Steelers will next play the Tampa Bay Buccaneers on the road in Week 6.
